PHASE 1.6 - CalculationsPurpose: to find the weight of our rocket and surface area to see how much fins we need in order to have a balanced weight of the rocket Group Members: Isabel and Sammie ____________________________________________________________________________________________________ Background Research; There was no real research besides finding out how to calculate Directions:
SURFACE AREA = Circumference times Height. ___________________________________________________________________________________________________ What Happened? - A calculation story We first found the midpoint of our rocket. We then had Braden mark it with sharpie. We then calculated the the surface area of 1. AREA 1: 1.25 (diameter) x PI = Circumference 3.925 3.925 x 6 in (height) = 23.55 SURFACE AREA = 23.55 AREA 2: 1.25 (diameter) x PI = Circumference 3.925 3.925 x 8 in (height) = 31.4 SURFACE AREA =31.4 AREA 3: 1.25 (diameter) x PI = Circumference 3.925 3.925 x 5.75 in (height) = 22.568 SURFACE AREA = 22.568 AREA 4: (Must do 1.25 x 1.25 times PI) 1.25 (diameter) to the power of 2, x PI = Circumference 4.908 SURFACE AREA = 4.908 Once we calculated all the surface areas, we added 2 and 3. AREA 2 + AREA 3 + AREA 4 = 22.568 + 31.4 + 4.908 = 58.876 Then we subtracted AREA 1 from all else. 58.876 - 23.55 = 35.326 which means we need a surface area total of 35.326 of our fins added all together somehow to have a balanced weight. FINS: We had already made our fins. So instead of actually making new ones, we must calculate if our surface area is enough with our current fins. Since our fins are strangely shaped, Braden had to cut them in different sections and we had to make more calculations. We had four fins so we just had to 1. Find areas of 1-6 2.Add them together 3.Multiply by 4 4.See if they're enough or if we need more SURFACE AREA = B x H /n2 AREA 1: 1.75/2 x 3.25 = 2.84 Surface Area= 2.84 AREA 2: 1.90/2 x 1.75 = 1.66 Surface Area = 1.66 RECTANGLE SURFACE AREA = L times H AREA 3: 1.80/2 X 3.30 = 5.94 Surface Area = 5.94 AREA 4: 0.75/2 x 3.75 = 1.406 Surface Area: 1.406 AREA 5: 0.40/2 x 1.80 = 0.36 Surface Area = 0.36 AREA 6: 0.35/2 x 1.75 = 0.577 Surface Area = 0.577 Add up all of these calculations and have the final surface area.
TOTAL SURFACE AREA OF ONE FIN = 12.783 12.783 X 4 FINS = 51.132 SURFACE AREA ____________________________________________________________________________________________________ FINAL THOUGHTS: This means that we have more than enough weight for our fins. We cover the necessary surface area our rocket covers. We don't need to add anymore or less to our rocket. Our fins will stay the same We will just add a few coins to our nose cone to balance out the weight.
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December 2015
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